20y^2+31y+12=0

Solution for 20y^2+31y+12=0 equation:

Simplifying
20y2 + 31y + 12 = 0

Reorder the terms:
12 + 31y + 20y2 = 0

Solving
12 + 31y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + 5y)(3 + 4y) = 0

Subproblem 1
Set the factor '(4 + 5y)' equal to zero and attempt to solve:

Simplifying
4 + 5y = 0

Solving
4 + 5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 5y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 5y = 0 + -4
5y = 0 + -4

Combine like terms: 0 + -4 = -4
5y = -4

Divide each side by '5'.
y = -0.8

Simplifying
y = -0.8
Subproblem 2
Set the factor '(3 + 4y)' equal to zero and attempt to solve:

Simplifying
3 + 4y = 0

Solving
3 + 4y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 4y = 0 + -3
4y = 0 + -3

Combine like terms: 0 + -3 = -3
4y = -3

Divide each side by '4'.
y = -0.75

Simplifying
y = -0.75
Solution
y = {-0.8, -0.75}